What are the five categories of my plate

What are the five categories of my plate

2 months ago

Solution 1

Guest Guest #9792762
2 months ago

Hello!

The 5 categories of my plate are...

Fruits

Vegetables

Grains

Protein

Dairy

I attached an image also.

Solution 2

Guest Guest #9792763
2 months ago
TheBlueFox is right. It is Vegetables, fruits, grains, protein, and dairy :)

ūüďö Related Questions

Question
helppppppppppppppppppppppppppppppppppppppppppppppppppp
Solution 1

Answer:

Working on answer.....

Explanation:

This is an automated message sent by the brainly + the parikh association.

Solution 2

Answer:

1) C

2) B

3) D

4) B

5) A

6) C

7) B

8) D

9) A

10) B

Explanation:

Equation of a  straight  line is y= m x + c

m = slope

c is y- intercept

1) y = (-1/2)x + c

substitute (5,-2)  for (x, y) points in the equation above

c = (1/2)

Therefore, the equation of the line is  y = (-1/2)x + (1/2)

substituting the options A  to D in to the equation to check for equality we find that option C does not lie on the Line  it should have been (4, -1.5)

2) y = (3/4)x + c

substitute (3,3)  for (x, y) points in the equation above

c = (3/4)

Therefore, the equation of the line is  y = (3/4)x + (3/4)

substituting the options A  to D in to the equation to check for equality we find that option B does not lie on the Line  it should have been (-6, -3.75)

3) y = (-1/5)x + c

substitute (-7,2)  for (x, y) points in the equation above

c = (3/5)

Therefore, the equation of the line is  y = (-1/5)x + (3/5)

substituting the options A  to D in to the equation to check for equality we find that option D does not lie on the Line  it should have been (4, -0.2)

4) y = (1/2)x + c

substitute (9,3)  for (x, y) points in the equation above

c = (-3/2)

Therefore, the equation of the line is  y = (1/2)x - (3/2)

substituting the options A  to D in to the equation to check for equality we find that option B does not lie on the Line  it should have been (6, 1.5)

5) y = (-2/3)x + c

substitute (5,3)  for (x, y) points in the equation above

c = (1/3)

Therefore, the equation of the line is  y = (-2/3)x + (1/3)

substituting the options A  to D in to the equation to check for equality we find that option A does not lie on the Line  it should have been (-3, 2.333)

6) y = (1/4)x + c

substitute (5,2)  for (x, y) points in the equation above

c = (3/4)

Therefore, the equation of the line is  y = (1/4)x + (3/4)

substituting the options A  to D in to the equation to check for equality we find that option C does not lie on the Line  it should have been (4, 1.75)

7) y = (-3/2)x + c

substitute (3,-4)  for (x, y) points in the equation above

c = (1/2)

Therefore, the equation of the line is  y = (-3/2)x + (1/2)

substituting the options A  to D in to the equation to check for equality we find that option B does not lie on the Line  it should have been (2, -2.5)

8) y = (3/5)x + c

substitute (3,2)  for (x, y) points in the equation above

c = (1/5)

Therefore, the equation of the line is  y = (3/5)x + (1/5)

substituting the options A  to D in to the equation to check for equality we find that option D does not lie on the Line  it should have been (-4, -2.2)

9) y = (1/3)x + c

substitute (5,1)  for (x, y) points in the equation above

c = (-2/3)

Therefore, the equation of the line is  y = (1/3)x - (2/3)

substituting the options A  to D in to the equation to check for equality we find that option A does not lie on the Line  it should have been (6, 1.333)

10) y = (-3/4)x + c

substitute (-5,4)  for (x, y) points in the equation above

c = (1/4)

Therefore, the equation of the line is  y = (-3/4)x + (1/4)

substituting the options A  to D in to the equation to check for equality we find that option B does not lie on the Line  it should have been (-2, 1.75)

Question
I GIVE THE BRAINLIEST


YOU MUST ANSWER ALL THE QUESTIONS!



1.A plant that has no ovary would not be able to form which structure?


filament

fruit

petals

sepal


2.Jack needs to determine the missing flower part in this set:


pistil, stigma, style, _____


Which part of a flower best completes the set?


anther

petals

stamen

ovary


3.Which structure becomes the seed after fertilization?


ovary

anther

ovule

pollen


4.Farah makes a Venn diagram to compare monocots with dicots.


Which label belongs in the region marked X?


Angiosperm

Cotyledon number

Leaf structure

Vascular bundle structure




5.Which label belongs in the region marked X?


Angiosperm

Cotyledon number

Leaf structure

Vascular bundle structure


6.If the pollen in a plant were not able to form a tube, which process would still be able to happen?


dispersal

fertilization

pollination

seed development


7.What are the two kinds of angiosperms?


pollinators and fertilizers

monocots and dicots

rhizomes and bulbs

stamen and pistils


8.Examine the sentence that Eunice wrote to describe the male reproductive parts of a flower.


The filament is the main structure, which is made up of the stamen with the anther on top.


Which statement best describes Eunice’s sentence?


It correctly describes the male reproductive parts.

Eunice switched the stamen and the anther.

Eunice switched the filament and the stamen.

It correctly describes the female reproductive parts.


20 POINTS

The image is for the question 4
Solution 1

Answer:

1. Fruit

2. Ovary

3. Ovule

4. Leaf Structure

5. Vascular bundle structure

6. Dispersal

7. Monocots and Dicots

8. Eunice switched the Filament and Stamen

Solution 2

Answer:

1. Fruit

2. Ovary

3. Ovule

4. Leaf Structure

5. Vascular bundle structure

6. Dispersal

7. Monocots and Dicots

8. Eunice switched the Filament and Stamen

i just took the test so yeah the gut before was right

Question
A good letter of recommendation:‚Äč
Solution 1

Answer:

D) conveys unique qualities about a student

Explanation:

A good letter of recommendations would have a lot of good things about the student, so it would be more than a page long.

Schools want to hear good things about students, so it would D.

Solution 2
D. Conveys unique qualities about a student
Question
I am stuck on this assignment
Solution 1
1) fix ‚Äúcruising to alaska‚ÄĚ to ‚Äú a cruise in alaska‚ÄĚ
2) composed to composition
3) reforming to reformed
4) exportation to exporting
5) sense to sensing
Question
Help me please with it
Solution 1

Answer:

D

Explanation:

Double the first equation. Write the second below it. Rearrange the second.

2x - 20 = - 4y

-2x -16= +4y           Add.

- 36 = 0

There is no solution to this pair of equations.

Solution 2
It is no solution. hope this helps
Question
Help!!. What is the surface area of this sandwhich.
ANSWeR QUICK
Solution 1
5‚ÄĘ2= 10 / (10‚ÄĘ3) 3 = sides so 30
5‚ÄĘ4=20
5‚ÄĘ3=15
30+20+15= 65in^2
Question
Plz help me with this question!!
Solution 1

Answer:

B)x^3

Explanation:

Given,

(x^8)/(x^2)=y^12

We can simplify the following by bringing the (x^2) above the division line which makes the power negative.

(x^8)*(x^-2)=y^12

or,(x^(8-2))=y^12

or,x^6=y^12 .........(1)

The question is, (y^8)/(y^2)=

Simplifying the question,

(y^(8-2))

or,y^6

Now,from ...(1),

x^6=y^12

or,(x^3)^2=(y^6)^2

Removing the squares,

x^3=y^6

Thus,we get the answer of the question,

(y^8)/(y^2)=y^6=x^3

Question
what is the difference between a lemon and a lime.
Solution 1

Lemons and limes are highly acidic citrus fruits. Limes are green, small, and generally more acidic than lemons. Lemons are yellow and larger than limes. Both fruits have good nutritional qualities. There pH is also different take a look at the picture below.

Solution 2

Limes and lemons are from the same citrus fruit family, rich in vitamin C but different in color. Limes are green and smaller, whereas lemons are yellow and big in size. Despite the differencein flavor, color and size; limes andlemons have the same nutritional benefits and are low in calories.

Question
How do you solve? Please answer this question ASAP!!
Solution 1

Answer:

280

Explanation:

For ease of comparison $20/hr < $12/hr+ commission, let's do it by the hour first.

Hourly pay of the food truck is $12, every burger she sells, she gets 10% of the $12 burger, which is $1.2. Therefore all we need to figure out is 1.2x +$12 > $20. Minus both sides by 12, now all we have is down to the bare minimum: 1.2*X = $8

8 divided by 1.2 is 6.66 (infinite), but since she can't sell 0.6 of a burger, we need to round up, which is 7, keep in mind we are still at hourly. Now we know that she has to sell at least 7 burgers every hour she's working for the food truck, it's a 40-hour work week, 7*40 is 280.

Check:

Food truck: $12+ 12*0.1*7 = $20.4/hr  $20.4 > $20

Best of luck for your SAT!

Question
What is the value of X?
Solution 1

Answer:

x = 7

Explanation:

Because 25 is a perfect square of 5, we can turn

[tex]5^{3x - 5}[/tex] = [tex]25^{x + 1}[/tex]

into

[tex]5^{3x - 5}[/tex] = [tex]5^{2x + 2}[/tex]

Since the bases are now both equal, we can completely ignore them, as we are only trying to find x. This leaves us with:

3x - 5 = 2x + 2

All we have to do now is solve for x:

x - 5 = 2          Subtract 2x from both sides.

x = 7                Add 5 to both sides.

Hope this helps! :)

Solution 2

Answer:

x = 7

Explanation:

To solve for x in this equation, we're going to need to get the two exponents (3x - 5 and x + 1) equal to each other, but we can't do that unless our bases are the same.

For example, in [tex]A^{x} = B^{x + 1}[/tex], you cannot solve x = x + 1. In [tex]A^{x} = A^{x + 1}[/tex], you can solve x = x + 1.

Just by looking at the bases, 5 and 25, you can tell that it will be simple to make them match. 25 is just 5². The tricky part is going to be figuring out where to put the 2 into x + 1.

Let's look at another example. If you have [tex]2^{2 * 2}[/tex], then you can simplify it to [tex]2^{4}[/tex], which is 16. Or, you could do them one at a time, so [tex](2^{2}) ^{2}[/tex]. This way you'd have 4², which you'd be able to recognize as 16. Based on this example, we know that to make our bases the same, we need to change [tex]25^{x + 1}[/tex] to [tex]5^{2(x + 1)}[/tex].

[tex]5^{3x-5} = 25^{x+1}[/tex]   Change the right side to [tex]5^{2(x + 1)}[/tex]

[tex]5^{3x-5} = 5^{2(x+1)}[/tex]   Simplify that exponent using distribution

[tex]5^{3x-5} = 5^{2x+2}[/tex]  

Now that the bases match, you can get rid of them and just set the exponents equal to each other and solve for x.

3x - 5 = 2x + 2   Add 5 to both sides

3x = 2x + 7   Subtract 2x from both sides

x = 7

Now, check you work!

[tex]5^{3x-5} = 25^{x+1}[/tex]   Plug in 7 for x

[tex]5^{3(7)-5} = 25^{(7)+1}[/tex]   Simplify

[tex]5^{21-5} = 25^{8}[/tex]   Simplify one more time

[tex]5^{16} = 25^{8}[/tex]   Plug these into a calculator if you have one

152587890625 = 152587890625   So you know that x = 7 is correct.