Solution 1
📚 Related Questions
A B
a. 3174 0522
b. 4165 1654
1) What is the sum of A and B if they represent unsigned 12-bit octal numbers? The result should be written in octal. Show your work.
3174
0522
---------
3716
b).
4165
1654
--------------
10111
Sorry. This is all that can be shown. The rest is all verbal.
input
-keyboard
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output
-monitor
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-speaker
-usb (flashdrive)
1. Approximately how many nights during the month would an observer be able to witness a waxing gibbous phase?
2. A full moon occurred on December 21st. State the date of the next full Moon in January.
3. How many days does it take for the Moon to revolve from position 8 to position 5?
4. State two specific motions that affect the daily locations of high and low tides of Earth.
5. Explain why no person on Earth would witness a lunar eclipse when the Moon is in position #4.
during which the moon appears more than half but less than fully lit, and is growing
as time goes on. In the picture, it's everything from position-3 to position-5. It's
one fourth of the entire cycle, which is 7.4 days, so you'd see it on 7 or 8 consecutive
nights.
(The complete cycle of phases is 29.53 days.)
2). The complete cycle of phases is 29.53 days. Any phase visible on December 21
is visible again on January 19 or January 20.
3). From position-8 to position-5 in the picture is 5/8 of all the way around.
(5/8) of (29.53) = 18.5 days.
4). The locations of high- and low-tides on the Earth are influenced by the position
of the moon and the rotation of the Earth.
5). A lunar eclipse is the result of the moon sailing into the Earth's shadow.
The Earth's shadow is out behind it, opposite to the sun, toward position-5
in the picture, not position-4.
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5. H
go to next slide if next slide is hidden. This is useful when you have one slides but don't know whether it would be apt while presenting. So in such case make that hidden. And while presenting use 'H' if that slide can be useful to your audience.
The term spam is used in the Internet to denote something that is not needed or required. Spam include search engine spam, instant messenger spam, forum spam and comment spam. An unsolicited commercial email is example for e-mail spam. Other example is receiving promotional messages from people or companies with which you have no relationship.
the heat, that's very bad for the CPU. (Scientists say the CPU 'fails'. Engineers say
the CPU 'dies'. Users say the CPU 'burns up'.)
If you look at the CPU in your computer, you'll see that it's mounted on a big black
piece of metal with lots of fins and grooves in it, called a "heat sink". There may
also be a little fan blowing air past the heat sink, to help take heat away from it.
The thermal grease carries heat from the CPU to the heat sink faster than if they
were just bolted together with nothing in between them.
Parallel circuit. On a wire you put the lights and one switch, on the other you put a resistor and another switch. (and the third wire contains the generator)
Answer:
The three bulbs can be connected in series to the battery B1, such that when switch SW1 is turned ON all three bulb turns ON with the same brightness. We now have the three resistors R1, R2, and R3 connected in parallel to the lamps LMP1, LMP2, and LMP3 respectively when SW2 turn on. SW2 is a Three Pole Single Throw switch. Please see attachment for the electric circuit diagram.
Explanation:
QUESTION
How do you make a circuit so 1 switch will turn on/off all the lights(3 lights) and a second switch will change the lights from all being the same brightness to all being different brightness?
ANSWER
List of Component Used For The Design Of The Electric Circuit
The three bulbs can be connected in series to the battery B1, such that when switch SW1 is turned ON all three bulb turns ON with the same brightness. We now have the three resistors R1, R2, and R3 connected in parallel to the lamps LMP1, LMP2, and LMP3 respectively when SW2 turn on. SW2 is a Three Pole Single Throw switch. Please see attachment for the electric circuit diagram.
1. 18Volt Battery ( two 9 Volts batteries connected in series)
2. Three Filament lamps LMP1=LMP2=LMP3= 6V 6W.
3. Three resistors of R1=100Ω, R2=12Ω and R3=3Ω
4. SPST Switch =SW1
5. TPST Switch = SW2
Since the battery is 18V and connected in series to all three lamps, it is capable of delivering 6V per lamp. Each lamp is 6W. So the resistance of the bulb can be determined using Ohm’s law.
V=IR, P=IV = V2/R, R=V2/P
Where I= Current
V= Voltage
R= Resistance
P = Power
Lamp Resistance RL= 62/6 =6Ω
Total resistance of the lamps connected in series Rs= 6+6+6 = 18Ω
The total current through the series resistor combination IS = Battery supplied voltage divide by RS =18/18 =1A
So each lamp will dissipate power PL= I2*R= 1*6 =6W
When switch SW2 is closed, there is now a resistor connected in parallel to each of the lamp which will now reduce the total resistance combination of the lamp and resistors to a values lower than 6Ω
Lamp1 has 100Ω connected in parallel to it to give a total resistance of 5.66Ω
Lamp2 has 12Ω connected in parallel to it to give a total resistance of 4Ω
Lamp3 has 3Ω connected in parallel to it to give a total resistance of 2Ω
The new total resistance of the circuit is now R=5.66+4+2 = 11.66Ω
The new total current flowing through the circuit I=18/11.66 = 1.54A
The power dissipated by each lamp with a new series current of 1.54A can now be recalculated as follows;
Power dissipated by Lamp 1 P1= 1.542*5.66Ω = 13.42W
Power dissipated by Lamp 2 P2= 1.542*4Ω = 9.49W
Power dissipated by Lamp 1 P1= 1.542*2Ω = 4.74W
From the power dissipated by the 3 bulbs, we can see that lamp 3 is bright, lamp 2 is brighter and Lamp 1 is the brightest of all the three lamps.